Sunday, February 13, 2011

Mastering Physics: Light on a Photoelectric Surface

When ultraviolet light with a wavelength of 400 nm falls on a certain metal surface, the maximum kinetic energy of the emitted photoelectrons is 1.10 eV.

Part A
What is the maximum kinetic energy K_0 of the photoelectrons when light of wavelength 310 nm falls on the same surface?
Use h = 6.63×10−34 J \cdot s for Planck's constant and c = 3.00×108 m/s for the speed of light and express your answer in electron volts.

  K_0 = 2.00
 {\rm eV}

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