Learning Goal: To understand the qualities of the finite squarewell potential and how to connect solutions to the Schrödinger equation from different regions.
Part A  

For a onedimensional wave function to be normalizable, it must go to zero as goes to infinity or negative infinity. Consider the wave function in the region . As goes to infinity, this must become zero. What does this imply about the constants and ?
Notice that the wave function is nonzero in the entire domain , even though this region would be forbidden by classical mechanics since . This "tunneling" into the classically forbidden region is a key difference between classical and quantum mechanics. Also notice that, since anywhere in the region, there is some small, but nonzero, probability of finding the particle hundreds of kilometers away from the potential well. 
Part B  

Now, consider the wave function in the region . As goes to negative infinity, this must become zero. What does this imply about the constants and ? (Be careful of signs.)
Again, you see that the wave function is nonzero throughout the entire classically forbidden region. 
Part C  

Recall that a physical solution to the Schrödinger equation must be continuous everywhere. Consider the two branches Express your answer in terms of and .

Part D  

The derivative must also be continuous everywhere to have a physical solution (unless there are points where the potential energy suddenly becomes infinite, which never happens for the finite square well). Take the derivative of the two branches that you looked at in Part C to find the value of . Express your answer in terms of , , and .

Part E  

Since you found that in Part C, you can now write the equations for the wave functions as Express your answer in terms of , , , and .

Part F  

The last boundary condition, continuity of the derivatives at , yields a similar equation: . Dividing this equation by your equation from Part E (and doing some algebra to simplify) gives . This is a transcendental equation, which must be solved numerically or graphically. However, since and both depend on , the energy levels for the finite squarewell bound states may be found from this equation. Instead of trying to do this, we will look at the behavior of this equation as . Solving for , you find . In this limit, what value does the righthand side of the equation approach? In other words, what is ? 

Part G  

This result tells you that, as goes to infinity, the equation reduces to . Substitute back in and solve for the energy levels in this limit. Use the fact that for any integer . Express your answer in terms of , , , and .
This result shows that the finite squarewell solution becomes the particleinabox solution as goes to infinity. Notice that seems to be allowed here, though it wasn't for the particle in a box. However, substituting gives a solution that cannot be normalized and thus is not a physical solution. 
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